Documentation

api.users.from_user_id

Fetch a user dictionary from a user ID.

Arguments:

def api.users.from_user_id(
  user_id: str = None,
):

Returns a dict in the form:

{
  'user_id': str,
  'email': str, # Primary user email
  'display_name': str,
}

Example:

user = api.users.from_user_id(user_id="abcdef123456")