api.users.from_user_id
Fetch a user dictionary from a user ID.
Arguments:
def api.users.from_user_id(
user_id: str = None,
):
Returns a dict in the form:
{
'user_id': str,
'email': str, # Primary user email
'display_name': str,
}
Example:
user = api.users.from_user_id(user_id="abcdef123456")